NewStats: 3,263,645 , 8,180,887 topics. Date: Saturday, 07 June 2025 at 02:50 AM 2z4u2v

aceman88:




Thanks so much my guy. the exam was written today. Your effort really helped a lot.

Mechanics96:


If the equations are really 3x+y=8 and x^2+x-y=6 then none of the options provided is correct!

I have provided the two values of y in my solutions and they are y=1.27 and y=26.73


If it was the right question that I solved, then I'm sure my solutions are right.

Cheers!

thank u

[quote author=Iamcyb
org post=61150594]thank u[/quot e]


It is not correct change the second eqtn

Hadampson:
Gurus in the house, please i need ur help on this questions

1) P, R, and S are points, O is the centre of the circle. If POR = 150degree. Calculate PSR

2) P, Q and R are point on a circle, centre of OPQ =36degree, what is the size of PRQ

3) In the diagram, O is the centre of the circle, if OD=DC and LDCB=16degree, calculate LAOE

Help please

Hadampson:
Help please

I'm on a journey bro, I"ll solve your questions tomorrow, God's willing

Hadampson:
Gurus in the house, please i need ur help on this questions

1) P, R, and S are points, O is the centre of the circle. If POR = 150degree. Calculate PSR

2) P, Q and R are point on a circle, centre of OPQ =36degree, what is the size of PRQ

3) In the diagram, O is the centre of the circle, if OD=DC and LDCB=16degree, calculate LAOE

2.

Pls provide the diagram for the third question

cyndylove64:
Pls can someone help me solve this set theory using expansion without venn diagram AuB=AnB .thanks u can send the working to this whatsapp number 08138273229

chat me me with this number. .to add u. 07064396712

If the maximum value of y = 1+ hx -3x^2 is 13, find h

EngrBello:
If the maximum value of y = 1+ hx -3x^2 is 13, find h

the maximum value occurs when the derivative (dy/dx=0) hence differentiating we have

h-6x=0; => x=h/6. so substitute x into the first equation, we get ymax=1+h(h/6)-3(h/6)^2= 1+(h)^2/6-(h)^2/12=1+(h)^2/12;

=> ymax=1+(h)^2/12; but we were told from the question that ymax=13; 13=1+h^2/12=> 12=h^2/12.

Hence h^2=144, which implies h =+12 or -12.

masperano:


the maximum value occurs when the derivative (dy/dx=0) hence differentiating we have

h-6x=0; => x=h/6. so substitute x into the first equation, we get ymax=1+h(h/6)-3(h/6)^2= 1+(h)^2/6-(h)^2/12=1+(h)^2/12;

=> ymax=1+(h)^2/12; but we were told from the question that ymax=13; 13=1+h^2/12=> 12=h^2/12.

Hence h^2=144, which implies h =+12 or -12.

Thanks

If y = 3cos4x , dy/dx equals

EngrBello:
If y = 3cos4x , dy/dx equals

let u=4x and hence y=3cosu
du/dx=4 and dy/du=-3sinu=-3sin4x
but dy/dx=dy/du * du/dx
dy/dx=4 * (-3sin4x)
dy/dx = -12sin4x

efficiencie:


let u=4x and hence y=3cosu
du/dx=4 and dy/du=-3sinu=-3sin4x
but dy/dx=dy/du * du/dx
dy/dx=4 * (-3sin4x)
dy/dx = -12sin4x

I got that as well....but the answer said; 24sin4x

A bag of rice feeds 15 students for 7days.How long would the same bag feed 10 students

EngrBello:

A bag of rice feeds 15 students for 7days.How long would the same bag feed 10 students

4 days and 16minutes

EngrBello:

A bag of rice feeds 15 students for 7days.How long would the same bag feed 10 students

It's indirect proportion so the right answer is (15 x 7)/10 =10. 5days = 10days, 12 hours

efficiencie:


4 days and 16minutes

Just a tip to answering maths and physics questions:

There are some questions that we may not really be able to solve, but we would be able to predict the answers. This question is one of them.

Without solving, one would automatically know the answer to the question above would be greater than 7days.

Because, If a bag can feed 15 students for 7days,
Then that same bag would logically feed a 'lesser number of 10 students' for a period of more than 7days.

This would be highly useful to jambites.
It's one of the tips to scoring high in UTME

There still no valid answer to the simultaneous equations below without manipulation...

X + Y = 5
X^X + Y^Y = 31

please, anybody with the right solution should help a brother.

Hi my fellow Mathematicians, we have a new facebook page that teaches secondary school Mathematics free. Here is the link https://www.facebook.com/lagosmathhometutors/. Please like our page and share the good news with a teacher or student who might need it

A boy lost 1/4 of his cards in a game of cards then won 6 more cards.if he had 7 cards less when he finished playing than when he started, how many did he start with.

Please help with this

Hello house. Sorry for derailing but I have a small problem in Chemistry that needs urgent attention.
Make up 50ml of HCL concentration at 25ppm from 100ppm
thanks.

Xsem:
A boy lost 1/4 of his cards in a game of cards then won 6 more cards.if he had 7 cards less when he finished playing than when he started, how many did he start with.

Please help with this

He must have started with 52 cards;

Let the no of cards he started with be x
x- 1/4x +6 = x-7
4x-x+24= 4x-28
x=24+28
x=52

[quote author=DrinkWater10 post=62387873]Hello house. Sorry for derailing but I have a small problem in Chemistry that needs urgent attention.
Make up 50ml of HCL concentration at 25ppm from 100ppm
thanks.[/quote
Here is the answer

Pls is dere whatsapp group for dis?

Mechanics96:


He must have started with 52 cards;

Let the no of cards he started with be x
x- 1/4x +6 = x-7
4x-x+24= 4x-28
x=24+28
x=52

thanks so much

[quote author=Nezy4Real post=62399606][/quote] thanks alot bro

Xsem:
A boy lost 1/4 of his cards in a game of cards then won 6 more cards.if he had 7 cards less when he finished playing than when he started, how many did he start with.

Please help with this

Here is the solution
Click on this link https://www.facebook.com/lagosmathhometutors/ to watch solutions to secondary school math problems for free on Facebook. We live to solve Math problems. And don’t forget to Like our page and share it with your friends and colleagues who might need it. Please spread our good work

[quote author=Nezy4Real post=62399606][/quote]
Hello bro I'm back here again. I'm having problem computing the report for the precipitation titration I carried out.
Looks like that number 1 should have been: moles of AgNO3 in volume of WATER used in titration,