NewStats: 3,263,409 , 8,180,023 topics. Date: Thursday, 05 June 2025 at 07:24 PM 1da3i

emenik08:
Who can solve this mathematics

Solve for x and y in

X^y + Y^x = 16
X + Y = 3

Thanks

graphical method oooo

pls I need help on this .......
if the mean X is d value of miew U of a random sample of size n from the normal population of a known variance $^2 show that the 100(1-¢)℅ confidence interval of the miew U.
U=miew
¢=alpha
X=xbar
Thank you

SHOW THAT WHAT IS WHAT ?

snowprince07:
pls I need help on this .......
if the mean X is d value of miew U of a random sample of size n from the normal population of a known variance $^2 show that the 100(1-¢)℅ confidence interval of the miew U.
U=miew
¢=alpha
X=xbar
Thank you

agentofchange1:
SHOW THAT WHAT IS WHAT ?

Please help out with this questions anyone. Studying for my exam tomorrow but don't know how to solve this please!

Laplacian
ProfmathIsland
thankyoujesus
mathemagician1

Please help me to check the above question. It is needed urgently, thanks.

Am Sorry Mojeed4, i ain't a statistician;

given a set of N points chosen randomly in a plane, using any three of the points how many triangles can one obtain? There's a prize for the solution with proof.

ok , ever heard of airy"s equation before ?

mojeed4:


Please help out with this questions anyone. Studying for my exam tomorrow but don't know how to solve this please!

Somebody shud solve dis
let H be a non-empty subset of a group G. Then the following are equivalent 1) H is a subgroup of G 2) for all a, b € H ab^-1 € H 3) for all a,b € H ab € H 4) for all a € H a^-1 € H prove 1,2,3,4

Laplacian:
Am Sorry Mojeed4, i ain't a statistician;

given a set of N points chosen randomly in a plane, using any three of the points how many triangles can one obtain? There's a prize for the solution with proof.

Make me sef try my luck, besides whats the price?

To the question
Since there are N points and 3 random points are to be chosen from it to form the triangle, this can be done by using combination.
I. E the number of triangle that can be formed by any three points chosen from N is NC3. So that we have
n! /(n-3)! 3!
So if N equals three, only one triangle will be formed sice 3C3 = 1. Like wise for four points, 4 triangles can be formed.

anybody reading maths from uniben?

pls guys, I need someone to recommend a good mathematics textbook use in 100level....in mathematics & education department

Laplacian:
Am Sorry Mojeed4, i ain't a statistician;

given a set of N points chosen randomly in a plane, using any three of the points how many triangles can one obtain? There's a prize for the solution with proof.

Since there are N points and 3 random points are to be chosen from it to form the triangle, this can be done by using combination.
Thus the number of triangle that can be formed by any three points chosen from N is NC3. I.e

N!/3!(N-1)!

Wey my money

jerome263:
pls guys, I need someone to recommend a good mathematics textbook use in 100level....in mathematics & education department

Pure Mathematics by Bunday

Additional Mathematics by Godman



dats all

PLEASE WHO CAN SOLVE
M+N=120
N+R=100
find N,M,R

MunAKeyzZ:
PLEASE WHO CAN SOLVE
M+N=120
N+R=100
find N,M,R

Hmmmm, different answers.

MunAKeyzZ:
PLEASE WHO CAN SOLVE
M+N=120
N+R=100
find N,M,R

This is a classic case of an inconsistent system of equations.

There are simply infinite answers.

Take for example
1. N = 50, M = 70, R = 50
2. N= 42, M =78, R = 58

...

#GodBlessNigeria

MunAKeyzZ:
PLEASE WHO CAN SOLVE
M+N=120
N+R=100
find N,M,R

Infinitely many answers
from
M-R=20
we av

M=20,N=100,R=0
M=10,N=110,R=-10
M=30,N=90,R=10
and so on
so its endless

ladokuntlad:

Pure Mathematics by Bunday
Additional Mathematics by Godman


dats all

Thanks sir, but where can I get dem and how much does each cost? am in delta

jerome263:

Thanks sir, but where can I get dem and how much does each cost?
am in delta

For Additional Mathematics by Godman, I think u can get that at any standard Bookshop(price 700-1400 forgot d price)

Pure Mathematics for Advanced Level by Bunday should also b in d same price range but u need to goto Science lovers Bookshop
or any university Bookshop

Help solve: Find the constant value of this expansion(2x^2 - 1/x)^6

seuntosyn:
Help solve: Find the constant value of this expansion(2x^2 - 1/x)^6

I have done justice to this in the other thread.

Pls help solve x^x=20
find x

fawaz050:
Pls help solve x^x=20
find x

2<x<3

ladokuntlad:

For Additional Mathematics by Godman, I think u can get that at any standard Bookshop(price 700-1400 forgot d price)

Pure Mathematics for Advanced Level by Bunday should also b in d same price range but u need to goto Science lovers Bookshop
or any university Bookshop

Thanks man

thankyouJesus:
2<x<3

can u show ur workings pls..beem confused or thinking its not possible i hav a particular question,but i was thinking if someone could solve this,then i would be able to solve the other question myself

fawaz050:
can u show ur workings pls..beem confused or thinking its not possible i hav a particular question,but i was thinking if someone could solve this,then i would be able to solve the other question myself

Sincerely, it was a guess work.

thankyouJesus:
Sincerely, it was a guess work.

it was helpful though i got d answer it was around 2.something sha

fawaz050:
can u show ur workings pls..beem confused or thinking its not possible i hav a particular question,but i was thinking if someone could solve this,then i would be able to solve the other question myself

Use graph to solve it
Or if advance in differentiation
Use Newton-raphson method

Find all real roots if f(x^(1/9)) = x^2-3x+9





Every mathematics competition is loaded with mind blowing questions that require critical thinking. What is the product of the maximum prime factor of the number of words of this problem and the minimum prime factor of the number of words of this problem?


solve.
x+y+z=-2
x^2+y^2+z^2=14
x^3+y^3+z^3=-20




try the above guys...

agentofchange1:
SHOW THAT WHAT IS WHAT ?

its a proof of d formulae for confidence interval. I have gotten d proof thanks