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Nairaland Mathematics Clinic (520730 Views)
saipn: 8:30am On Nov 21, 2015 |
Pls gurus in the house help me to solve this SET world problem 1)In a class of 35 students,19 take history and 12 take economics. If 5 takes both subjects,how many take neither? 2)In a class of 36 students,29 do mathematics and 20 do chemistry. If 5 students do neither,how many students do chemistry but not mathematics? 3)In a school of 750 students,320 are girls. 559 students do some kind of sport. If 101 girls do no sport,how many boys also do no sport? |
dprinz99(m): 8:32am On Nov 21, 2015 |
I must comend u guys first for this grt work. I'm new on this thread and I think God hs Brot me to d ryt plc. my story goes dis way, while in sec school,I thought I will study medical course as such wouldn't need much maths.i wasn't interested in math anymore. I dropped futhermath in my ss2 even thou I was abv average. as life changes,I now hv opportunity to go abroad for studies(which God hs done).and the course I want to pursue now requires excellent knowledge of maths(aerospace engr). aldo I'm NT doom in math's,Bt I must confess DAT my math knowledge is not up to DAT. I jus hav four month to d begin in of my course,I hv started self study.n I must it DAT I hv already seen d changes,Bt I want to b more than a GURU in math's. my question is,how can I become overgud in math's? what r d steps? what must I do? thankx |
petengine(m): 9:06am On Nov 21, 2015 |
dprinz99:it requires constant practice. "practice makes perfect". first start with the known (simple ones) then advance to the unknown (difficult ones). don't feel discourage if u don't get the practice questions right at first. my favorite quote then I was "if u leave maths for one day, maths will leave u for 1 week" so keep on practicing till u become morn than a guru in maths. cc: MathsChic, et al. |
dprinz99(m): 9:21am On Nov 21, 2015 |
saipn: . (1) 35:::19plus12plus x 35:::31plus x x::::35-31 x::::4 therefore,4 student take neither |
dprinz99(m): 9:24am On Nov 21, 2015 |
petengine: I'm grateful bro |
Mathemagician1(m): 9:40am On Nov 21, 2015 |
saipn: (1) In a class of 35 students,19 take history and 12 take economics. If 5 takes both subjects,how many take neither? Solution: Total students = 35 History student = 19 Economics students = 12 Students taking both courses = 5 Economics = (12 - 5)= 7 History = (19 - 5) = 14 Neither = 35 - ( 14 + 7 + 5) = 9 (2) In a class of 36 students,29 do mathematics and 20 do chemistry. If 5 students do neither,how many students do chemistry but not mathematics? Solution: Total students = 36 Mathematics students = 29 Chemistry students = 20 Neither = 5 Both = ((29 - x) + (20 - x) + x + 5) - 36 = 18 Chemistry = 20 - 18 = 2 (3) In a school of 750 students,320 are girls. 559 students do some kind of sport. If 101 girls do no sport,how many boys also do no sport? Solution: Total students = 750 Total Sport student = 559 Girls population = 320 Boys population = (750 - 320) = 430 Non-sport activity girls = 101 Sports active girls = (320 - 101) = 219 Sports active boys = (559 - 219) = 340 Non-sport activity boys = (430 - 340) = 90 |
ladokuntlad(m): 11:08am On Nov 21, 2015 |
saipn:1) 35=(19-5)+(12-5)+5+x 35=14+7+5+x 35-26=x X=9 2) 36=(29-x)+(20-x)+x+5 36=54-x 36-54=-x -18=-x X=18 thus chemistry only gives 20-18=2 3)solved already by mathemagician1 |
stlaibrowne(m): 2:26pm On Nov 21, 2015 |
Mathemagician1: saipn:The solutions of question 2 above is all wrong. The question is chemistry only
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ladokuntlad(m): 3:32pm On Nov 21, 2015 |
stlaibrowne:i got mine naa |
stlaibrowne(m): 4:28pm On Nov 21, 2015 |
ladokuntlad: Oh yes boss the other two foul foul foul |
Mathemagician1(m): 5:15pm On Nov 21, 2015 |
stlaibrowne: ![]() |
dprinz99(m): 6:16pm On Nov 21, 2015 |
1/3plus(5/7(9/10-1plus3/4)) its fraction. I hv tried by stil no ryt anxa plx help |
Mathemagician1(m): 6:34pm On Nov 21, 2015 |
dprinz99: 1/3 + ( 5/7 ( 9/10 - 1 + 3/4 )) Using BODMAS 1/3 + ( 5/7 ( 9/10 - 1/4 )) 1/3 + ( 5/7 ( 13/20 )) 1/3 + ( 13/28) 1/3 + 13/28 = 67/84 |
seuntosyn: 11:45pm On Nov 21, 2015 |
Help solve this (3/4 --2/5) - 1/3 of 3/10 all divided by 2 -- (1/1 3/7) moreso i want sir to teach me sets
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ladokuntlad(m): 12:46am On Nov 22, 2015 |
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seuntosyn: 6:42am On Nov 22, 2015 |
[quote author=ladokuntlad post=40275175] is it like dis? NOPE (3/4-(-2/5))-1/3 of 3/10 all dived by (2-(-1/(1 3/7)) ) i made a mistake when typing is like this (3/4 - 2/5) - 1/3 of 3/10 all divided by 2 - (1/1 3/7) |
dprinz99(m): 6:46am On Nov 22, 2015 |
Mathemagician1:I got that Bt its NT the ryt ansa ooo |
jackpot(f): 6:47am On Nov 22, 2015 |
Simplify as much as possible logca * logcb
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Mathecian(m): 7:31am On Nov 22, 2015 |
dprinz99:67/27? |
ladokuntlad(m): 8:17am On Nov 22, 2015 |
jackpot:check ur question again. because dis has already been simplified. maybe dia ought to b a little modification in yaa log except u looking for dis logca * logcb= logc(a+b) wich is very wrong |
ladokuntlad(m): 8:21am On Nov 22, 2015 |
seuntosyn: ((3/4-(2/5))-(1/3x3/10))/(2-(1/(1 3/7)) ) ((3/4-2/5)-(1/10))/(2-(1/(10/7)) ) (7/20-1/10)/(2-7/10) (5/20)/(13/10) =5/20 x 10/13 =5/26 According to ur new question |
ladokuntlad(m): 8:28am On Nov 22, 2015 |
dprinz99:then d mistake is from the way u typed d question. Try tak a snapshot of the question and it here |
jackpot(f): 2:24pm On Nov 22, 2015 |
ladokuntlad:okay. What of the following: Simplify as much as possible: (logc a) / (logcb) |
stlaibrowne(m): 2:27pm On Nov 22, 2015 |
jackpot: Logc(a-b) |
thankyouJesus(m): 4:05pm On Nov 22, 2015 |
ladokuntlad(m): 5:07pm On Nov 22, 2015 |
jackpot: (logc a) / (logcb) =(loga/logc)/(logb/logc) =(loga/logc)*(logc/logb) =(loga/ =loga/logb =logb a QED |
ladokuntlad(m): 5:08pm On Nov 22, 2015 |
jackpot(f): 6:50pm On Nov 22, 2015 |
thankyouJesus:kudos to you and ladokuntlad |
saipn: 7:40pm On Nov 22, 2015 |
stlaibrowne:thanks bro |
saipn: 7:42pm On Nov 22, 2015 |
ladokuntlad:thanks ladokuntlad |
saipn: 7:42pm On Nov 22, 2015 |
ladokuntlad:thanks ladokuntlad |
saipn: 7:44pm On Nov 22, 2015 |
Mathemagician1:thanks mathematicians |
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