NewStats: 3,263,924 , 8,181,902 topics. Date: Sunday, 08 June 2025 at 07:18 PM 2ec3k

To square any number which is between 25-50.say 46.say 46-25(the lower range)=21.then say 50(the higher range)-46=4 and square the four to give 16.take the two together to get 2116...let's try that of 48.you say 48-25=23.then 50-48=02 and square it to give 04.take it together to get 2304

J.Rika:
Try dat of 30. got a wrong answer.

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I'm done with statistics oo. .. Statistics fu n mass communicator.. Jor oo

Emmyk: I'm done with statistics oo. .. Statistics fu n mass communicator.. Jor oo

wrap me on 2go let's communicate...am also a 100lstdnt of mass communication, Ahmadu bello university,zaria..

What's ur name. Kogi State Uni, 200level.

Try dat of 30. got a wrong answer.

Sodiq3:
wrap me on 2go let's communicate...am also a 100lstdnt of mass communication, Ahmadu bello university,zaria..

.ok...add me with mathemagician on 2go

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To multiply any number by 5,50,500 etc...let's use a manipulation as this...5=10/2.so assuming you want to multiply 448 by 5.just divide 448 by 2 and add a nought...therefore 448/2=224.then add a nought to give 2240.assuming you want to multiply 363 by 50...divide 363 by 2 and add 2 noughts.363/2=181.5 and add 2 noughts to give 18150...

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Pls.nairalanders.i want you to post more of this...if you don't know any...just type your comment to impress those that are typing it...there are still many more of these...i still lay emphasis on square,if you show that you like this thread...i will post multiplication to the extent that you can go to the examination hall without calculator...also need a magic to know trig. Functions sin and cos offhand.just comment on this thread...

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Nice one bro. . . .keep it up!

To know if a number is divisible by 9...just add the numbers together,if it's a multiple of 9.then 9 will surely go in it...e.g.747...you say 7+4+7=18...18 is a multiple of 9...then 9 is a factor of 747...what about 735...add the numbers 7+3+5=15...15 is not a multiple of 9...therefore 9 is not a factor of 735.THE SAME RULE APPLY FOR 3...THEREFORE 735 IS A MULTIPLE OF 3 BECAUSE 15 IS A MULTIPLE OF 3

visit www.mathsvillage.org today for solution to maths past question

Ride on guru

Calculusf(x):
To know if a number is divisible by 9...just add the numbers together,if it's a multiple of 9.then 9 will surely go in it...e.g.747...you say 7+4+7=18...18 is a multiple of 9...then 9 is a factor of 747...what about 735...add the numbers 7+3+5=15...15 is not a multiple of 9...therefore 9 is not a factor of 735.THE SAME RULE APPLY FOR 3...THEREFORE 735 IS A MULTIPLE OF 3 BECAUSE 15 IS A MULTIPLE OF 3

Does this also apply to all numbers?

Ortarico:

Does this also apply to all numbers?

...not all bro,we will meet at 2go to sort the remaining

Hi, pls can u teach me how to multiply numbers in different bases apart from base 10? I really need it.

Omosivie,:
Hi, pls can u teach me how to multiply numbers in different bases apart from base 10? I really need it.

...base 10...is generally use by everyone...but when i get any trick for any other base,i will let you know

Calculusf(x):
...not all bro,we will meet at 2go to sort the remaining

All right Prof

Calculusf(x):
...base 10...is generally use by everyone...but when i get any trick for any other base,i will let you know

Ok, thanks. Can u pls help me out with this question: Simplify log 25^x(base 5) - log0.04(base 5).

Omosivie,:
Ok, thanks. Can u pls help me out with this question: Simplify log 25^x(base 5) - log0.04(base 5).

Lemme help you....
Log₅25^x - log₅
log₅5^2(x) - log₅(4/100)
2xlog₅5 - log₅(1/25)
2x*1 - (log₅5/log₅5²
2x - 1/2 = 0
2x = 1/2
x = 1/4

Ortarico:

Lemme help you....
Log₅25^x - log₅
log₅5^2(x) - log₅(4/100)
2xlog₅5 - log₅(1/25)
2x*1 - (log₅5/log₅5²
2x - 1/2 = 0
2x = 1/2
x = 1/4

Thanks, but ur answer is not among the options. The options are:
A 2x+1
B 2x+2
C x/2
D 2x-2.
I hope u can understand my workings cos i don't know how to use subscript and superscrpit on nairaland cos i'm on mobile. Log25^x(base 5) - log 4/100(base 5)
log5^2x(base 5) - log 5^-2(base 5)
NB: log5(base 5) = 1.
2x-(-2)
2x+2. My final answer is 2x+2 but the textbook says it's 2x-2. Can u pls point out my mistake?

Omosivie,:
Thanks, but ur answer is not among the options. The options are:
A 2x+1
B 2x+2
C x/2
D 2x-2.
I hope u can understand my workings cos i don't know how to use subscript and superscrpit on nairaland cos i'm on mobile. Log25^x(base 5) - log 4/100(base 5)
log5^2x(base 5) - log 5^-2(base 5)
NB: log5(base 5) = 1.
2x-(-2)
2x+2. My final answer is 2x+2 but the textbook says it's 2x-2. Can u pls point out my mistake?

...you are very right bro with what you did,i can't say the textbook is wrong,maybe it's typographical error,i mean the answer the textbook provided but your answer is right...

Omosivie,:
Thanks, but ur answer is not among the options. The options are:
A 2x+1
B 2x+2
C x/2
D 2x-2.
I hope u can understand my workings cos i don't know how to use subscript and superscrpit on nairaland cos i'm on mobile. Log25^x(base 5) - log 4/100(base 5)
log5^2x(base 5) - log 5^-2(base 5)
NB: log5(base 5) = 1.
2x-(-2)
2x+2. My final answer is 2x+2 but the textbook says it's 2x-2. Can u pls point out my mistake?

Yes you're right, cause with the options it's easier to work out what/how the examiner wants the equation to be.

@ortarico @calculus i'm very proyd of u both. I'll love to meet you both in persons

Thanks, I still have some questions i'd like u guys to solve. Can I post them here?

Omosivie,:
Thanks, I still have some questions i'd like u guys to solve. Can I post them here?

...don't worry sister,if you have any other question,just type it...we will try our best...but nobody is an iceland of knowledge...

oyestephen: @ortarico @calculus i'm very proyd of u both. I'll love to meet you both in persons

Thanks boss. By God's grace we'll meet at the university of first choice...

Omosivie,:
Thanks, I still have some questions i'd like u guys to solve. Can I post them here?

You can. We'll help with the help of God!